MATLAB Answers

How can I find the sum of the perimeter of a matrix?

31 views (last 30 days)
Alexandra Huff
Alexandra Huff on 5 Aug 2016
Answered: Ibrahim Abouemira on 19 May 2019
Hi, I am wondering if I had a matrix [1,2,3;1,2,3;1,2,3] how I could find the sum of the perimeter. Thanks an advance.

  0 Comments

Sign in to comment.

Accepted Answer

dpb
dpb on 5 Aug 2016
One way amongst any number...
>> M=[1,2,3;1,2,3;1,2,3];
>> I=ones(size(M)); I(2:end-1,2:end-1)=0;
>> S=sum(reshape(M.*I,1,[]))
S =
16
>>

  0 Comments

Sign in to comment.

More Answers (3)

Stephen Cobeldick
Stephen Cobeldick on 5 Aug 2016
Edited: Stephen Cobeldick on 5 Aug 2016
In one line is easy and very fast:
>> M = [1,2,3;1,2,3;1,2,3];
>> sum(sum([M([1,end],2:end-1),M(1:end,[1,end]).']))
ans = 16

  5 Comments

Show 2 older comments
dpb
dpb on 5 Aug 2016
Yes, it isn't nearly as good numerically, agreed...
dpb
dpb on 10 Feb 2018
[ ... Ricardo Florez Answer moved to comment since was a follow-up question on earlier Answer syntax ... dpb]
Hi. Why is it necessary to write two "sum" in the code: sum(sum(M(...)? Please see below:
the sum(M(:))-sum(sum(M(2:end-1,2:end-1)))
Thank you.
dpb
dpb on 10 Feb 2018
Because sum(M(2:end-1,2:end-1)) is a row vector of the sums of the columns in the submatrix; to get the total have to then add those values. This is taken care of in the first sum by the use of the special syntax (:) that returns all elements of an array/matrix in a column so sum only needs to add the one column vector. There is no syntax in Matlab to apply the secondary indexing operation to the result of the first function call return; there've been many suggest the enhancement.

Sign in to comment.


Sanjay Zamindar
Sanjay Zamindar on 28 Jun 2018
Edited: dpb on 28 Jun 2018
function final_sum = peri_sum(A)
size_row = size(A,1)
size_col=size(A,2)
Sum_of_first_row = sum (A(1, [1:1:end])); %base
Sum_of_first_Colmn = sum(A([2:1:size_row],1))
%sum_col= sum(A([2:1:size_col], [1:size_col:size_col]));
Sum_of_last_column= sum(A([2:1:size_row],size_col))
sum_of_last_row = sum(A(size_row,[2:1:size_col-1]))
final_sum = sum_of_last_row+ Sum_of_last_column+Sum_of_first_Colmn+Sum_of_first_row
end

  0 Comments

Sign in to comment.


Sign in to answer this question.