I have a matlab code in which I am dividing the numerator with (t2-t1). It shall be actually in differential form. How to do that?

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Annu Panwar on 19 Mar 2017

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Edited: Matt J on 19 Mar 2017

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y= (10a+ 4)/(t2-t1)
z=(10a +4)
a= constant, not a changing value

I want the equation in dz/dt form

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Roger Stafford on 19 Mar 2017

If z is a constant, then necessarily dz/dt = 0.

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