bitget function is not invoking output bits in a vector
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Anmar Mohammed
on 26 Nov 2018
Edited: Anmar Mohammed
on 26 Nov 2018
k=k+1; %% k is counter and its chainging even more than (length(A))
for t = 1:1:length(A) %% A is a vector contains 8 elements
recovered_bits(1,k)= bitget(A(1,t),1); % extract LSB of each element in array and put them (LSB) in recovered_bits vector
k=k+1;
end
%% Output ----> recovered_bits = [] knowing that i trying to preallocate the vector previously
Accepted Answer
madhan ravi
on 26 Nov 2018
Edited: madhan ravi
on 26 Nov 2018
You don't need a counter for this case , please pre-allocate before loop!
recovered_bits=cell(1,length(A)); %proper pre-allocation
for t = 1:length(A)
recovered_bits{t}= bitget(A(1,t),1);
end
[recovered_bits{:}]
2 Comments
madhan ravi
on 26 Nov 2018
Anytime :), see Steven Lords answer which is the efficient way to do what you are doing
More Answers (2)
Steven Lord
on 26 Nov 2018
Why loop?
r = randi([0 intmax('int8')], 8, 1, 'int8');
recovered_bits = bitget(r, 1);
result = [r, recovered_bits, mod(r, 2)]
The second and third columns of result should be the same.
1 Comment
KALYAN ACHARJYA
on 26 Nov 2018
Edited: KALYAN ACHARJYA
on 26 Nov 2018
Initiallize k=1, otherwise K is not defined
k=1; %% k is counter and its chainging even more than (length(A))
for t = 1:1:length(A) %% A is a vector contains 8 elements
recovered_bits(1,k)= bitget(A(1,t),1); % extract LSB of each element in array and put them (LSB) in recovered_bits vector
k=k+1;
end
2 Comments
KALYAN ACHARJYA
on 26 Nov 2018
Edited: KALYAN ACHARJYA
on 26 Nov 2018
For example I have choosen different A
A=[4 6 7 4 3 0 8 4];
for t=1:1:length(A) %% A is a vector contains 8 elements
recovered_bits(t)=bitget(A(1,t),1); % extract LSB of each element in array and put them (LSB) in recovered_bits vector
end
%% Output ----> recovered_bits = [] knowing that i trying to preallocate the vector previously
disp(recovered_bits);
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