counting the number of values in table if the condition satisfies??
34 views (last 30 days)
Show older comments
Hi,
I have 2 tables as
a =
y=
If the string in "y" matches with string in ''a'' i want to count all the strings after matching the strings.
I am looking for looping only not like count command.
Thanks in advance
9 Comments
Guillaume
on 27 Mar 2019
Edited: Guillaume
on 27 Mar 2019
Why is U a table as opposed to the simpler
U = 'car';
?
Why is xx a table as opposed to simply a cell array?
You don't seem to know how to index cell arrays, tables or matrices. If A is matrix, A{i} is an error.
So in your example, is the desired result 4? (4 strings after 'car')
Accepted Answer
dpb
on 27 Mar 2019
xx = categorical({'computer'; 'car'; 'mobile'; 'bus'; 'tree'; 'jeep'});
u='car';
[ia,ib]=ismember(u,xx);
if ia
count=numel(xx)-2+1; % inclusive count
else
count=nan; % not found indicator
end
tables unnecessarily complicate life when they really have no useful reason for using them in a given case.
Using categorical for such variables simplilfies comparisons greatly; that's what they're for.
Above for a one-at-a-time lookup, loop over an array of u if needed...
2 Comments
Guillaume
on 28 Mar 2019
That count line should be:
count = numel(XX) - in + 1;
However, you could just replace the whole lot by:
count = numel(XX) - find(u == XX, 1);
In the above case, there's no benefit to using categorical. You could just stick to a cell array, in which case you replace the == by strcmp
More Answers (0)
See Also
Categories
Find more on Language Fundamentals in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!