Overlaying and Comparing Two Sets of Co-Ordinates
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Hello all
I have been using Matlab as a fancy calculator for some time now but always wanted to do more with it.
So part of trying to learn Matlab I was wanted to tackle an actual problem which I was hoping the community could help with.
I have 2 x sets of data, they are data set 1 and data set 2.
Data set 1contains a list of X Y co-ordinates (which I have created a matrix for), the data relates to an outline of a building. 
Data set 2 also contains a list of X Y co-ordinates (which I have also created a matrix for), this data relates to the outline of the same building, the only difference is that data set 2 contains more data X Y co-ordinates and the values of each X and Y differ slightly.
Plotting these data sets gives me the following:-

What I am trying to do is overlay data set 2 with data set 1 such that the best fit is found.
Once the images are overlaid as best as they can I then want to compare the original X Y co-ordinates of data set 2 with the adjusted/best fit co-ordinates of data set 2 to see the difference.
I am struggling with how to overlay the two sets of co-ordinates to produce a best fit – any ideas?
Thank you.
2 Comments
  Matt J
      
      
 on 13 Apr 2019
				What kind of transformations of data set 2 (to match data set 1) are you willing to allow? Translations? Rotations? Something even more complicated?
Accepted Answer
  Matt J
      
      
 on 14 Apr 2019
        
      Edited: Matt J
      
      
 on 14 Apr 2019
  
      I haven't used it myself, but this implementation of Iterative Closest Point seems pretty popular
4 Comments
  Matt J
      
      
 on 15 Apr 2019
				I deduce from this section of the help docunentation
%   OUTPUT:
%
%   R - rotation matrix
%   T - translation vector
%   data2 - matrix with transformed data points,   [ P_1 P_2 ... P_N ]
%
%           data2 = R*data + T
that the "data" input (not the "model") is the data that floats. It is "data" to which the rotation and translation are being applied at the very end.
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