Could anyone suggest me is there any way of choosing maximum and minimum values together

Asked by jaah navi on 17 Oct 2019

Latest activity Commented on by Jos (10584) on 17 Oct 2019

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A = [23 42 37 18 52];

With respect to command M = max(A) gives 52

min(A) gives 18

Is there any way so that i can get both 52 and 18 together(maximum and minimum together)

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dpb on 17 Oct 2019

mnmx=[min(A) max(A)];

or write your own "syntactic sugar" routine minmax()--

function mnmx=minmax(x)
  mnmx=[min(x(:)) max(x(:))];
end

The latter should probably also have the ability to return the locations to mimic builtin interfaces.....and maybe treat arrays the same as them also in working on column-basis by default with the dimension as the optional argument...so many choices to make.

3 Answers

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Answer by Walter Roberson on 17 Oct 2019

https://www.mathworks.com/help/matlab/ref/bounds.html

[A_min, A_max] = bounds(A)

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Answer by Jos (10584) on 17 Oct 2019

Here is a nice trick that also allows you to combine functions in a single call, which also can return the other outputs of these functions:

minmaxFun = @(x) cellfun(@(F) F(x), {@min, @max}) ;
[V, I] = minmaxFun([2 1 3 5 2])
% V = [1 5], I = [2 4]

You can take this a step further:

mapF = @(val, fcns) cellfun(@(f) f(val{:}), fcns) ;
data = randi(10, [1 10])
[minmax, minmaxIDX] = mapF({data}, {@min @max})
S = mapF({data}, {@mean @median @std})

You can learn much more about this at Loren's Blog:

https://blogs.mathworks.com/loren/2013/01/10/introduction-to-functional-programming-with-anonymous-functions-part-1

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Answer by Daniel M on 17 Oct 2019

Edited by Daniel M on 17 Oct 2019

A = [23 42 37 18 52];
minmaxVals = prctile(A,[0 100])
ans =
  18    52

3 Comments

jaah navi on 17 Oct 2019

ok.But when i tried with respect to the following array

A=[1.0992    1.5107    1.6426
6664    2.7159    2.7833
7849    0.4077    0.3900
0745    1.0196    1.0966
5537    0.6946    0.8196
6301    1.6503    1.7238]
minmaxVals = prctile(A,[0 100])

it gives the following output

minmaxVals =[ 0.0752    0.1222;
    2.8012    1.6739]

I want to make these values to run into the following code;

C=zeros(6,1);
[value, index] = min(A,[],2)   %      [value, index] = minmaxVals(A,[],2)
V=value;
I=index;
C(:,1) = index  

Could you please help me on this.

Walter Roberson on 17 Oct 2019

As I have been telling you: use the simple ways first and get them working, and do not worry about fancy ways until you have significant performance problems.

So just call min() and max() instead of spending a lot of time looking for a function that will return the values and indices. Or write a small function yourself that uses min and max internally to return what you want.

Jos (10584) on 17 Oct 2019

I second that, Walter! +1

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