Is it possible to do this without a loop

Is it possible to create a vector like this without a loop?
I have only managed v2 with a loop that goes like this:
for k=1:100
v2(k)=cos(k*pi/8)
end

Answers (2)

Try this:
n = 1 : 100
v2 = cos(n * pi / 8)
n = 1 : 30
v3 = n .* exp(n/10)
Arthur Roué
Arthur Roué on 16 Mar 2020
Edited: Arthur Roué on 16 Mar 2020
% The cos function operates element-wise on arrays
v2 = cos((1:100)*pi/8);

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on 16 Mar 2020

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