How to multiply a scalar with matrix within loop and for each iteration store the values in new matrix?

I have a matrix of 24x365 but just to explain what I want to do I am taking here an example matrix of 2x2.

A=[1 2

3 4]

b=0.1

n=3 (no of years)

The new matrix for each year must be formed in a way that for first year it should be simply C(1)=A but for second year the scalar b is multiplied with the C so C(2)=b*C(1).For third year it should be C(3)=b*C(2) and so on...

The answer matrix should be like

C(1)=[1 2

3 4]

C(2)= [0.1 0.2

0.3 0.4]

C(3)=[0.01 0.02

0.03 0.04]

I have formed this code but I am not getting the desired results.

clc

clear all

A=[1 2;

3 4];

b = 0.1

n=3;

c=b*a;

d=c;

for i=1:n

c(1)=d

c(i+1)=b*c(i);

end

The error appears as "Unable to perform assignment because the left and right sides have a different number of elements

Error in Untitled (line 11)

c(1)=d"

Can anyone please help me???

Answer 1

[Matt J]

There is no need for a loop:

C=A.*reshape(b.^(0:n-1),1,1,[]);

[Rabia Zulfiqar]

Thanks alot:)