Using 3d matrix inmatlab

A(:,:,1) =

     1     1     0
     0     1     1
     1     1     1

A(:,:,2) =

     1     0     0
     0     0     1
     0     0     1

I used [r,c,v] = ind2sub(size(A),find(A == 1)); to find r,c,v in matrix A that has a value 1. But I want to place a condition that while A == 1 then I(r,c) = v

for example I(1,1) = {1,2} since for v=1,2 A takes a value 1. Please help me out with a code.

Answer 1

[Matt J]

 [m,n,p]=size(A);
 s=reshape(1:p,1,1,p);

 A=bsxfun(@times,A,s);

[jana]

I wanted to put them as sets. example I(1,1) = {1,2} that is (1,1) takes value 1 at v ={1,2}. My matrix should look more like : [{1,2} 1 1; 0 1 {1,2}; 1 1 {1,2}]

[Matt J]

 [m,n,p]=size(A);
 s=reshape(1:p,1,1,p);
 l=num2cell(bsxfun(@times,A,s),3);
 l=cellfun(@(c) nonzeros(c).',l,'uni',0);

 l(cellfun('isempty',l))={0}

[jana]

l=cellfun(@(c) nonzeros(c).',l,'uni',0); it shows an error message : Input # 2 expected to be a cell array, was double instead.

[jana]

Navermind I fixed it. Thankyou!