# Pearsons correlation using corrcoef not working

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Elizabeth Lees on 24 Mar 2021
Commented: William Rose on 24 Mar 2021
I am trying to calculate the pearsons correlation between two variables in a timetable. I am utalising the corrcoef() function. However the output it gives me is always NaN NaN NaN NaN. Why is this? How can I fix this?
Elizabeth Lees on 24 Mar 2021
@William Rose Thank you for your answer. I have discovered it was because many rows of the numerical data contained NaN values, I have now used 'Rows', 'Pairwise' to discard these in the statistics and am now recieving results. However when just the NSE() function to calculate the Nash-Sutcliffe value between the variables I am still getting an NaN result I believe for the same problem however 'Rows', 'Pairwise' doesn't seem to work within the NSE() function, do you know of another way to discard these empty rows to calculate the Nash-Sutcliffe?
Example code:
NSE(combined_data.Observed_Rio_Branco,combined_data.Simulated_Rio_Branco, 'Rows', 'pairwise')
Error using NSE
Too many input arguments.

William Rose on 24 Mar 2021
This code eliminates each row with one or more NaNs. Thank you to @Jan for this.
X = rand(10, 4);
X(X < 0.1) = NaN;
disp(X); %array containing NaNs
X(any(isnan(X), 2), :) = []; %delete rows with NaN
disp(X) %array with NaN rows removed
William Rose on 24 Mar 2021
Assumng your input data are column vectors, you would do
%make a Nx2 array
A=[combined_data.Observed_Rio_Branco,combined_data.Simulated_Rio_Branco];
A(any(isnan(A), 2), :) = []; %delete rows with NaN
NSE(A(:,1),A(:,2));
I do not have the NSE() function so I cannot test the code above.

R2018a

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