Error using textread to read data containing "INF" or "NaN" with float data
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I have a file with data showing date,time, and floating point data downloaded from an instrument. Some instances of the floating point data were recorded as "INF" meaning the data record was skipped or erroneous. See the sample data below:
"2012-02-15 06:34:00",965,0,1.367,-61.03,-4.838,8.64,281.8,-1.367,-56.2,"INF",-61.03,-3.471,-57.56,296.5,352.7
"2012-02-15 06:35:00",966,0.946,1.802,-60.79,-4.656,8.66,281.8,-0.856,-56.14,1.904,-59.85,-2.854,-56.99,296.8,352.9
"2012-02-15 06:36:00",967,1.325,1.926,-60.82,-5.14,8.67,281.8,-0.602,-55.68,1.454,-59.5,-3.214,-56.29,296.8,352.5
I have tried to read the data using the following line:
[d1,counter,SR01Up,SR01Dn,IR01Up,IR01Dn,NR01TC,NR01TK,NetRs,NetRl,Albedo,UpTot,DnTot,NetTot,IR01UpCo,IR01DnCo] = textread([direct filename], '%22c %u %f %f %f %f %f %f %f %f %f %f %f %f %f %f','headerlines',4,'delimiter',',');
When I do, I get the following error;
Error using dataread
Trouble reading floating point number from file (row 966, field 11) ==> "INF",-61.03,-3.471,-57.56,2
Error in textread (line 176)
[varargout{1:nlhs}]=dataread('file',varargin{:});
Error in CR3000dataproc2 (line 89)
[d1,counter,SR01Up,SR01Dn,IR01Up,IR01Dn,NR01TC,NR01TK,NetRs,NetRl,Albedo,UpTot,DnTot,NetTot,IR01UpCo,IR01DnCo]
= textread([direct filename], '%22c %u %f %f %f %f %f %f %f %f %f %f %f %f %f %f
Kindly help resolve this...
Vincent
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Answers (4)
Matt Kindig
on 26 Jul 2013
Try using textscan() with the 'TreatAsEmpty' option:
output = textscan([direct filename], '%22c %u %f %f %f %f %f %f %f %f %f %f %f %f %f %f','delimiter',',', 'EmptyValue', NaN,'TreatAsEmpty', '"INF"');
d1= output{1};
counter = output{2}; %etc.
All the "INF" should now be converted to NaN.
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dpb
on 26 Jul 2013
NB the character format "%22c" will end up returning the trailing comma as well as the two surrounding '"' marks on the date field as the actual date field is only 19 characters wide w/ leading and trailing double quotes to surround an embedded space in the string.
Using
fmt=['"%19c" %u' repmat('%f',1,14)];
will return just the actual date/time string w/o additional post-processing to use it.
With 'collectoutput', 1 the first record is returned w/ the above fmt as
'2012-02-15 06:34:00' [965] [1x14 double]
instead of as
'"2012-02-15 06:34:00",' [965] [1x14 double]
Just a nit, but eliminates one additional step later...
dpb
on 26 Jul 2013
Edited: dpb
on 26 Jul 2013
Here's a case where the "red-haired stepchild" status of textread hurts--it can't accept a custom 'TreatAsEmpty' string property. Use textscan instead.
Unfortunately, textscan has its own quirks; the most irritating of which is it can't return anything except a cell array... :(
>> l='"2012-02-15 06:34:00",965,0,1.367,-61.03,-4.838,8.64,281.8,-1.367,-56.2,"INF",-61.03,-3.471,-57.56,296.5,352.7 ';
>> fmt=['%s %u' repmat('%f',1,14)];
>> textscan(l, fmt,'delimiter',',','treatasempty',{'"INF"'},'collectoutput',1)
ans =
{1x1 cell} [965] [1x14 double]
>>
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Vincent Odongo
on 27 Jul 2013
1 Comment
per isakson
on 27 Jul 2013
Try
cac = textscan([direct filename], '%22c %u %f %f %f %f %f %f %f %f %f %f %f
%f %f %f','headerlines',4,'delimiter',',','EmptyValue', NaN,'TreatAsEmpty',
'"INF"');
and markup your text
dpb
on 27 Jul 2013
Edited: dpb
on 28 Jul 2013
[d1,counter,...,IR01DnCo] = textscan([direct filename], ...
On running the script I get the following error; Error using textscan Too many output arguments.
Well, yes, as per the doc, textscan returns ONLY a cell output.
doc textscan
As I showed earlier for the typical line
l='"2012-02-15 06:34:00",965,
0,1.367,-61.03,-4.838,8.64,281.8,-1.367,-56.2,"INF",
-61.03,-3.471,-57.56,296.5,352.7 ';
and the format string
fmt=['"%19c" %u' repmat('%f',1,14)];
C=textscan(l, fmt,'delimiter',',','treatasempty',{'"INF"'},'collectoutput',1)
C =
'2012-02-15 06:34:00' [965] [1x14 double]
Also as noted previously there's a problem w/ an earlier respondent's format of '%22c' for the date/time string in doesn't character-match the leading/trailing '"' and picks up the delimiter comma as well as the actual data in the string is only 19 characters long--it's wrapped in " for the embedded spaces (21 char's total). The length of 22 then gets the delimiter, too.
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