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Split a Number Sequence into n equal parts and then replacing the values in the matrix.

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Mark Wood
Mark Wood on 23 May 2021
Edited: Jonas on 24 May 2021
How to split a number sequence into n equal parts and then and then replace the value of matrix with it.
For Example:
A 5x5 Matrix(A) is given to us :
Now we will find the maximum element in this matrix using : M = max(A, [], 'all')
Now we want to quantize this max number ie. 29 into n equal parts. Example : Now starting from 0 to 29 ([0:29]) I want to split this sequence to 3 equal parts.
Such that my output now looks like:
0 - 0:9
1 - 10:19
2 - 20:29
Now I want to replace the number that are lying between 0 to 9 with 0, 10 to 19 with 1 and 20 to 29 with 2 from the given matrix.
Such that my final matrix becomes,
Please help with the MATLAB Code?

Accepted Answer

Matt J
Matt J on 23 May 2021
Edited: Matt J on 23 May 2021
result = discretize(A, linspace(0, max(A(:)), 4) )-1
  5 Comments
Jonas
Jonas on 24 May 2021
@Matt J i think that was meant to be a comment for another answer below, there is an exact copy of the coment

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More Answers (2)

Jonas
Jonas on 23 May 2021
Edited: Jonas on 24 May 2021
i suggest normalizing the matrix by dividing all elements through the biggest value you already have and multiply it afterwards with the number of intervals you want (3 in the example). then you can apply the floor() function. the values equal to the maximum value have to be decreased by one at the end (e.g. 29 will become 3 and then has the be decreased to 2, all other wntries are already correct)
nrOfIntervals=3;
A=A/max(A(:));
A=A*nrOfIntervals;
A=floor(A);
A(A==nrOfIntervals)=nrOfIntervals-1;
edit: a correct version can be found in the comments of this answer
  2 Comments
Jonas
Jonas on 24 May 2021
my bad, this should work better:
nrOfIntervals=3;
A=A/max(A(:));
A=A*nrOfIntervals;
A=ceil(A);
A(A>0)=A(A>0)-1;

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Girijashankar Sahoo
Girijashankar Sahoo on 23 May 2021
N= 25 % length of sequence
n=sqrt(N) % break the sequence in n element
X=randi(30,1,25)
A=reshape(X,[n,n])
M=max(A,[],'all')
split=M/3
for i=1:n
for j=1:n
Value=A(i,j)
if Value<(M/split)
A(i,j)=0;
elseif (M/split)<Value<(2*M/split)
A(i,j)=1;
else Value>(2*M/split)
A(i,j)=2;
end
end
end

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