# manually-written floor function code for rounding non-integers

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Hi,

I need your help. See what I get when I used edit to view the steps involved into the floor function. It is a built-in function but I still want to see the mathematics on which this floor function is based on via matlab codes. Can you help? E.g., If floor (2.3) = 2. I want to see a mathematical expression that grabs 2 and/or discards 0.3 to output 2.

%FLOOR Round towards minus infinity.

% FLOOR(X) rounds the elements of X to the nearest integers

% towards minus infinity.

%

% See also ROUND, CEIL, FIX.

% Copyright 1984-2005 The MathWorks, Inc.

% Built-in function.

##### 0 Comments

### Accepted Answer

John D'Errico
on 8 Jul 2021

Edited: John D'Errico
on 8 Jul 2021

If you want a mathematical expression, WRITTEN in MATLAB (where it will not have been written in the actual code) this could work:

myfloor = @(x) double(int64(x));

myfloor(2.3)

After converting the floating point number to an integer, then it needs to be returned as a double. But that code would be better written to return a number of the same floating point class, since that would fail for single precision input. As well, for input that was already an integer class, it should not convert the result to a double. Finally, that code will fail for negative numbers, since floor(-2.3) is -3.

floor(-2.3)

myfloor(-2.3)

Negative numbers round down for floor. A simple function that will effectively work for numbers of any sign is:

mybetterfloor = @(x) x - mod(x,1);

floor([-2.3 2.3])

mybetterfloor([-2.3, 2.3])

As you can see, this code rounds down for negative numbers, as does floor itself.

x = randn(1,10000);

all(floor(x) == mybetterfloor(x))

No explicit cast to another class was done in that code, so it should work for any floating point or integer class. Is that how they implemented it in compiled C? Surely not.

##### 2 Comments

Stephen23
on 8 Jul 2021

Edited: Stephen23
on 8 Jul 2021

When converting to integer MATLAB rounds to the nearest whole number, rather than chopping off the fractional part (as apparently C users assume all other languages must also do):

x = 2.6;

double(int64(x))

The MOD solution works well though:

x-mod(x,1)

x = -2.6; % negative too

x-mod(x,1)

### More Answers (2)

Matt J
on 8 Jul 2021

Edited: Matt J
on 8 Jul 2021

If floor (2.3) = 2. I want to see a mathematical expression that grabs 2 and/or discards 0.3 to output 2.

There is no fundamental formula for the floor function. In C\C++ it is done simply by casting the input to an integer type. One way to implement it manually though would be,

myfloor(2.3)

function y=myfloor(x)

y=str2double( extractBefore(string(x),'.') );

end

Kapil Gupta
on 8 Jul 2021

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