Does r=uint64(308436464205151562) make sense? It seems like the argument to uint64 is a double precision number, so you have already lost the precision you are trying to gain by using uint64.
r=uint64(308436464205151562) outputs for uint64(r) 308436464205151562. However, r=308436464205151562 outputs for uint64(r) 308436464205151552. A very small loss in precision, but still a loss. The Challenge set has some numbers that use all the paint if full precision math was used. If residual paint was required as an output then full precision is needed. For solutions using p=p-2*r-1 the errors in r and p may cause issues.
Very novel input parameter adjustment to allow direct solution.
That's Muller's method which is more computationally realiable than Bhaskaracharya's.
Nice bisecting search method and anonymous function for clean appearance.
Remove any row in which a NaN appears
Summing Digits within Text
Encode Roman Numerals
Fibonacci-Sum of Squares
GJam 2014 China Rd A: Library Sorting (Large)
Cody Matlab Version
Find Index of maximum Value and maximum Value of a vector
Rubik's Cube: 30 Moves or Less : Cody Size
Create Circular Perfect Square Sequence
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