This Challenge is to solve Question A of the USC ACM Fall 2012 Contest.
Given an array M of Valid binary codewords(m codewords of width n) and a Received Corrupted(?) codeword of width n, determine the minimum number of flipped bits in the Received codeword to generate a valid codeword.
Input: [ M, v ]
Output: e, minimum number of error(flipped) bits .
From full USC data file
Input: [0 0 0; 1 1 1; 1 1 0], [0 1 0]
Output: 1 as [0 1 0] can convert to [0 0 0] or [1 1 0] with a single flip
Matlab one-liner?
The Winning C solution - not much help:
#include <iostream>
#include <stdio.h>
#include <string>
using namespace std;
int main () {
freopen("codes.in", "r", stdin);
int K,n,b;
cin >> K;
for (int i = 1; i < K + 1; ++i) {
cin >> n >> b;
string m[1000], r;
for (int j = 0; j < n; ++j)
cin >> m[j];
cin >> r;
% Process Start
int f = b;
for (int j = 0; j < n; ++j) {
int d = b;
for (int k = 0; k < b; ++k) {
if (m[j][k] == r[k])
--d;
}
f = ((f <= d) ? f : d);
}
% Process End
printf("Data Set %d:\n", i);
printf("%d\n\n", f);
}
return 0;
}
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