Tanya, you like triangles.
These are interesting
a = sqrt(c^2-b^2);
this isn't a calculation!
test_1 a=sqrt(3) is longer than b=1
the good solution would be
a= min(sqrt(c^2 -b^2),b)
Kudos for finding this solution - it did indeed meet all the test cases, but wasn't quite what I had in mind! I will add a new test.
Project Euler: Problem 2, Sum of even Fibonacci
Back to basics 5 - Clipboard
Determine Whether an array is empty
Side of a rhombus
Is this triangle right-angled?
Length of the hypotenuse
Side of an equilateral triangle
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office