FYI, there is no known algorithm for optimal Egyptian fractions. Therefore this problem should allow the trivial solution of p/q as 1/q times p, which is not currently (this could be the worst score, a penalty can be included for repeated denominators). The solution for this problem is a greedy one (which may produce huge denominators), or the combination of non-greedy techniques that breaks the problem into several smaller pieces and which may create a huge sequence. I hope that the author has tested for upper and lower bounds on the test suite numbers since he is requesting an unknown solution and random numbers.
And my advice is if you do find a solution for this which attends the general case, don't publish it here, write a scientific paper.
Find the sum of the elements in the "second" diagonal
Convert String to Morse Code
Polite numbers. Politeness.
Divisible by 13
Divisible by n, Composite Divisors
Arithmetic/geometric sequence, 50/50
Which permutation is it?
Another colon problem
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