Suppose f and g are function_handles, try to define f+g,f-g,f*g and f/g.
if f = @(x)x and g = @(x)x+1
f+g = @(x)2*x+1
f-g = @(x)-1
f*g = @(x)x*(x+1)
f/g = @(x)x/(x+1)
hardly read it.Never thought a function_handle can be created like this.
brilliant solution! I used 'switch...case...' structure to judge 'type'.
Twins in a Window
Are all the three given point in the same line?
Sum of odd numbers in a matrix
replace empty matrices with ''
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office