Problem 44076. GJam 2017 Kickstart: Vote (Small)

Created by Richard Zapor

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>This Challenge is derived from</w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://code.google.com/codejam/contest/6304486/dashboard#s=p1\"><w:r><w:t>GJam 2017 Kickstart Vote</w:t></w:r></w:hyperlink><w:r><w:t>. This is the first 100 small cases with 0&lt;=M&lt;N&lt;=10.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:hyperlink w:docLocation=\"http://code.google.com/codejam\"><w:r><w:t>Google Code Jam 2017 Qualifier</w:t></w:r></w:hyperlink><w:r><w:t> is March 7, 2017. Typically four challenges with small and large aspects with 27 hours to complete.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The GJam story is given N and M votes, where N&gt;M, determine the number of voting sequences for which N is always in the lead divided by the total number of sequences(N+M)!.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Input:</w:t></w:r><w:r><w:t> [N,M], the quantity of votes to N and M</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Output:</w:t></w:r><w:r><w:t> [V], the ratio of N always leading sequences to total sequences</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Examples:</w:t></w:r><w:r><w:t> [N,M] [V]; [2,1] [0.33333333]</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>For the case [2,1] there are 6 sequences [N1N2M1,N2N1M1,N1M1N2,N2M1N1,M1N1N2,M1N2N1] with only the first two always having N in the lead.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Theory:</w:t></w:r><w:r><w:t> Brute force permutations and counting will not succeed in a timely manner for 0&lt;=M&lt;N&lt;=10 as 19! is a bit big to enumerate. Determining the inherent mathematical pattern is usually the best way to succeed in GJam. </w:t></w:r><w:r><w:t> </w:t></w:r><w:hyperlink w:docLocation=\"http://code.google.com/codejam/contest/6304486/scoreboard#vf=1\"><w:r><w:t>GJam Kickstart solutions(C++,Python)</w:t></w:r></w:hyperlink><w:r><w:t>.</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

This Challenge is derived from <a href = "http://code.google.com/codejam/contest/6304486/dashboard#s=p1">GJam 2017 Kickstart Vote</a>. This is the first 100 small cases with 0&lt;=M&lt;N&lt;=10.<a href = "http://code.google.com/codejam">Google Code Jam 2017 Qualifier</a> is March 7, 2017. Typically four challenges with small and large aspects with 27 hours to complete.The GJam story is given N and M votes, where N&gt;M, determine the number of voting sequences for which N is always in the lead divided by the total number of sequences(N+M)!.Input: [N,M], the quantity of votes to N and MOutput: [V], the ratio of N always leading sequences to total sequencesExamples: [N,M] [V]; [2,1] [0.33333333]For the case [2,1] there are 6 sequences [N1N2M1,N2N1M1,N1M1N2,N2M1N1,M1N1N2,M1N2N1] with only the first two always having N in the lead.Theory: Brute force permutations and counting will not succeed in a timely manner for 0&lt;=M&lt;N&lt;=10 as 19! is a bit big to enumerate. Determining the inherent mathematical pattern is usually the best way to succeed in GJam. <a href = "http://code.google.com/codejam/contest/6304486/scoreboard#vf=1">GJam Kickstart solutions(C++,Python)</a>.

Solve

Solution Stats

12 Solutions
9 Solvers

Last Solution submitted on Feb 19, 2019

Last 200 Solutions

Problem Recent Solvers9

Problem Tags

2017 gjam vote

Problem 44076. GJam 2017 Kickstart: Vote (Small)

Solution Stats

Last 200 Solutions

Problem Recent Solvers9

Suggested Problems

More from this Author236

Problem Tags

Problem 44076. GJam 2017 Kickstart: Vote (Small)

Solution Stats

Last 200 Solutions

Problem Recent Solvers9

Suggested Problems

More from this Author236

Problem Tags

Players