Given a matrix, find the average of the second largest values in each row. The same value does not exist on a row.
input x = [1 2 3 4;8 7 6 5;9 0 1 4] >>> output y = (3+7+4) / 3
solves the question yet the checker returns not a valid answer.
the following 4 lines solve this question
yet the online checker returns not a valid answer
Magic is simple (for beginners)
Reverse the elements of an array
Skip by a multiple
sum all digits
Add 3 (x<=100) Or Subtract 100 and add 3(100<x)
Please check the last row
The great 82-year-old
Let's make puddings !
Friday or not
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