Given a list of ordered pairs, and the order they should be placed in a line, find the sum of the absolute values of the differences.
list = [1 2
5 3
2 4
order = [1 3 2]
yields: [1 2][2 4][5 3]
or: abs(2-2) + abs(4-5)
or: 0 + 1
or: 1
Solution Stats
Problem Comments
3 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers911
Suggested Problems
-
1915 Solvers
-
Longest run of consecutive numbers
6655 Solvers
-
716 Solvers
-
1105 Solvers
-
Convert from Fahrenheit to Celsius
28618 Solvers
More from this Author51
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Is Test #3 correct? When I solve it with pencil and paper, I get 15 instead of 14.
[5 4][1 2][2 4][7 5][4 8][4 5][1 6]
= -3 + 0 + 3 + -1 + -4 + -4
= 3+0+3+1+4+4
=15
Have I missed something?
No it's 14. With the ordering, you should get:
[5 4][1 2][2 4][4 8][1 6][4 5][7 5], and the sum is abs(4-1) + abs(2-2) + abs(4-4) + abs(8-1) + abs(6-4) + abs(5-7) = 3 + 0 + 0 + 7 + 2 + 2 = 14
good