Borrowing the idea from Pascal Triangle, the following operation can be performed. Starting with an array of the first N even numbers (where N is greater than 1), the following upside-down triangle of numbers can be formed where starting from the second row, the number is determined by adding the two neighboring numbers in the previous row.
Given N, determine the last number at the bottom of the triangle (i.e., the red number in the illustration above).
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Last Solution submitted on Sep 24, 2026

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