Problem 1095. Circular Primes (based on Project Euler, problem 35)

Created by James

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The number, 197, is called a circular prime because all rotations of the digits: 197, 971, and 719, are themselves prime.

There are thirteen such primes below 100: 2, 3, 5, 7, 11, 13, 17, 31, 37, 71, 73, 79, and 97.

Given a number x, write a MATLAB script that will tell you the number of circular primes less than or equal to x as well as a sorted list of what the circular prime numbers are.

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Last solution submitted on Oct 18, 2019

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Ryan on 5 Dec 2012

Very nice problem!

Christopher on 5 Dec 2012

How do you return two separable outputs via a single vector?

James on 6 Dec 2012

Christopher, I should have been more clear in the problem description.

There are two outputs to the function. The first output (how_many) is a scalar, and is the number of circular primes.

The second output (what_numbers) is the vector containing the values of the circular primes.

Does this help?

Christopher on 18 Dec 2012

197 is not circular prime, because neither 791 nor 917 are themselves prime. Only test case 2 is correct.

James on 19 Dec 2012

Christopher, if our number is represented as ABC, then a cicrular prime is a number where ABC, BCA, and CAB are all prime. You are either shifting the numbers in the opposite direction or scrambling them. Not every permutation of the numbers has to be a prime number, although that in itself would be an interesting Cody problem. :-)

Tung Nguyen on 12 Oct 2019 at 6:12

wrong answer
Ask the group to review the results
917 is not a prime number and many other numbers the answer given by the team is completely wrong

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Solution 219006

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Jean-Marie Sainthillier on 19 Mar 2013

Size world record ?

Solution 176448

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Aurelien Queffurust on 12 Dec 2012

circul -ez y a rien à voir :)

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Problem 1095. Circular Primes (based on Project Euler, problem 35)

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Last 200 Solutions

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Problem 1095. Circular Primes (based on Project Euler, problem 35)

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Last 200 Solutions

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