Problem 13. Remove all the consonants

Created by Cody Team

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Last Solution submitted on Jan 20, 2022

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Problem Comments

18 Comments

18 Comments

Show 15 older comments

Matt Baran on 26 Jan 2012

I agree with the comments below, the test suite does not match the problem description.

Franck Dernoncourt on 26 Jan 2012

Agreed.

Ned Gulley on 3 Feb 2012

Fixing and rescoring. Sorry about the confusion.

Marlies on 27 Mar 2013

Though I think technically the problem description is correct, it would be much more understandable if you show what to do with punctuation as well.

Also, from the example it is not clear what one should do if two vowels exists in one word. Since it is not asked in the test-suite, maybe note explicitly that you can assume that every word will have one vowel at the most.

Rani V.S on 17 Jun 2014

interesting

Michel on 30 Mar 2015

http://www.oxforddictionaries.com/words/is-the-letter-y-a-vowel-or-a-consonant

Brian Butler on 16 Nov 2015

In the answer, spaces separate remaining characters except when preceeding punctuation!

Fatpuss on 13 Dec 2015

I keep getting "There was an issue submitting your solution. Remove inappropriate content." No idea why.

Erik Zdansky on 3 Feb 2016

This is just a "corollary" to the problem of removing vowels (with the same sample sentence!)

Jerivington on 30 May 2016

Brian Butler the spaces in the original sentence were included in the new sentence. It just seems the way you said it due to there being one vowel per word in the original.

Droopy Cee on 18 Mar 2017

I after 500 like i gave up but could distinguish between the two, I just wrote if and else and typed the thing. That counts right. XD I have no clue. lol I turned them into a double into a double figured out ' = 39 , space = 32 . = 46, It started Numbers = double(s1); Then I made vow = double(['AaEeIiOoUu.','''']) nothing wrong with that stuff. First one easy. The periods and little squirt marks in the second one. DX so stuck. Should I break it in two at the squirts and just make 2 strings. That's what I am thinking. It seem to have a mind of its own in the current form. It is just the spaces.

Ilias Patelakis on 6 Aug 2017

More test cases could be added as well. Such as if the sentence includes numbers, whitespaces, e.t.c.

ddd ppp on 9 Oct 2017

i hate this problem

Bhaskar R on 1 Aug 2018

After executing the the input string
s1 = 'I don''t want to work. I just want to bang on the drum all day.'
it is reading as single quote at "don''t " word but in the result both quotes are shown how it is possible????

Chris Coote on 10 Apr 2019

The vowels to retain here are, 'a e i o u'. There appears to be confusion for some.

Aaron Peterson on 7 Dec 2020

Can someone help me understand why this solution doesn't work? It may have something to do with the data types perhaps?

%Remove the consonants from a string
function s2 = refcn(s1)

L = length(s1);
matches = 0;

%increment through s1
for i = 1:L

flag = 0;

%compare the current letter to a vowel
if s1(i) == 'a'
flag = 1;
matches = matches + 1;
elseif s1(i) == 'e'
flag = 1;
matches = matches + 1;
elseif s1(i) == 'i'
flag = 1;
matches = matches + 1;
elseif s1(i) == 'o'
flag = 1;
matches = matches + 1;
elseif s1(i) == 'u'
flag = 1;
matches = matches + 1;
end

%Insert the matching vowel and a space
if flag == 1
s2(matches) = s1(i);
matches = matches + 1;
s2(matches + 1) = ' ';
end

end
end

Tianyi Yang on 8 Sep 2021

To solve this question, the best way is to delete consonants rather than to find 'a e i o u' and other things.
To be honest, although I know why there are two ' in the second test, I don't know how to detect it.
So, I give up and I choose to delete consonants. /(ㄒoㄒ)/~~

Rahul Gulia on 8 Oct 2021

s1 = 'Jack and Jill went up the hill'

% length(s1)
p = [];
for idx = 1:length(s1)
if s1(idx)=='a'
p = [p ' ' s1(idx)];
elseif s1(idx)=='e'
p = [p ' ' s1(idx)];
elseif s1(idx)=='i'
p = [p ' ' s1(idx)];
elseif s1(idx)=='o'
p = [p ' ' s1(idx)];
elseif s1(idx)=='u'
p = [p ' ' s1(idx)];
end
end

I am getting the correct answer in my Matlab for this. But the test case seems to cancel my solution.
Could anyone please point out my mistake here. Thanks in advance.

Solution Comments

Solution 1828542

1 Comment

1 Comment

josselin LEDENT on 28 May 2019

Y is no consonnant to me, but ok

Solution 1640002

1 Comment

1 Comment

xinyi yuan on 12 Aug 2021

???

Solution 1629275

1 Comment

1 Comment

Axel Forsman on 17 Sep 2018

Should clarify that 'y' is treated as a consonant.

Solution 1505551

1 Comment

1 Comment

Polina Malinina on 26 Apr 2018

It seems to be a mistake - in the second test S1 includes 'y' .That is not consonant, but the output S2 has not it.

Solution 1491584

2 Comments

2 Comments

Xinyue Zhou on 15 Apr 2018

tai tama nan le:)

Wei Wang on 23 Nov 2019

wo hao nan a

Solution 1432403

1 Comment

1 Comment

Axel Flament on 2 Feb 2018

y is a vowel !

Solution 1405581

2 Comments

2 Comments

Ajay Rawat on 5 Jan 2018

Why are there 2 apostrophes in answer of 2nd test?

Raymond MacNeil on 31 Dec 2019

Because if you do not double up (''), the single apostrophe is read by MATLAB as the end of the character vector. This is how you get around this.

Solution 1373033

1 Comment

1 Comment

mumu xu on 8 Dec 2017

take me some time to do ...

Solution 1360252

2 Comments

2 Comments

baquan wula on 28 Nov 2017

doc regexprep :'(?=[a-z])[^aeiou]' matches consonants.

Gustavo Morales on 13 Nov 2019

I think is the best solution!

Solution 1337594

2 Comments

2 Comments

Da Lu on 7 Feb 2018

Hi, I really like your solution.much easier than mine

Gustavo Morales on 13 Nov 2019

this solution just pass the test suite, but if there would be uppercase consonants, will fail!
The variable letter must contain the uppercase consonants too!

Solution 1294120

2 Comments

2 Comments

Alexis Marchesi on 17 Oct 2017

s1 = 'Jack and Jill went up the hill';
s2 = 'a a i e u e i';
assert(isequal(s2,refcn(s1)))
a = [] n = 30 s2 = [] a = 'a' s2 = 'a' s2 = 'a' s2 = 'a' s2 = 'a' a = 'aa' s2 = 'aa' s2 = 'aa' s2 = 'aa' s2 = 'aa' s2 = 'aa' a = 'aai' s2 = 'aai' s2 = 'aai' s2 = 'aai' s2 = 'aai' s2 = 'aai' a = 'aaie' s2 = 'aaie' s2 = 'aaie' s2 = 'aaie' s2 = 'aaie' a = 'aaieu' s2 = 'aaieu' s2 = 'aaieu' s2 = 'aaieu' s2 = 'aaieu' s2 = 'aaieu' a = 'aaieue' s2 = 'aaieue' s2 = 'aaieue' s2 = 'aaieue' a = 'aaieuei' s2 = 'aaieuei' s2 = 'aaieuei' s2 = 'aaieuei'

explain me why it doesn't work?

David Verrelli on 1 Nov 2017

Two things: (1) "y" is not normally considered a vowel, in everyday contexts; (2) you are omitting the spaces shown in s2 in the target solutions.

Solution 1294111

1 Comment

1 Comment

Alexis Marchesi on 17 Oct 2017

and y in test 2

Solution 887422

1 Comment

1 Comment

pranju chakrapani on 8 May 2016

can anyone help me solve this problem.

Solution 490157

3 Comments

3 Comments

Harish Maradana on 25 Aug 2014

function ans = refcn(s1)
regexprep(s1,'(?=[a-z])[^aeiou]', ' ','preservecase');
end
not working help me

Raihan Ahmed on 30 Aug 2015

write like this
s2=regexprep(s1,'(?![aeiou])[a-z]','','ignorecase');

Modesto Rosado on 22 Apr 2020

Raihan Ahmed, I know this comment is years old, but could you explain how the input '(?![aeiou])[a-z]' works? Obviously, MatLab recognises it as the same thing as '[b,c,d,f,g,h,j,k,l,m,n,p,q,r,s,t,v,w,x,y,z]', but what exactly is it doing?

Solution 219871

1 Comment

1 Comment

Cedric Wannaz on 21 Mar 2013

It looks like the test suit was modified and former solutions that were working are not working anymore.. so we are not competing on the same playground with new solutions..

Solution 204863

1 Comment

1 Comment

Edgar Guevara on 3 May 2013

the solution is not very pretty, try regular expressions

Solution 185760

1 Comment

1 Comment

sea knowledge on 4 Jan 2013

s1 = 'I don''t want to work. I just want to bang on the drum all day.';
the second case seems does not fit the meaning of the qustion! and l think it is totally unnecessary

Solution 124532

1 Comment

1 Comment

Chang Ho on 7 Aug 2012

just joking

Solution 123047

1 Comment

1 Comment

AlfredLeMark on 3 Aug 2012

lol y ^^

Solution 32725

1 Comment

1 Comment

Dan K on 7 Feb 2012

Generally "y" is not considered a consonant

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Problem 13. Remove all the consonants

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