Does r=uint64(308436464205151562) make sense? It seems like the argument to uint64 is a double precision number, so you have already lost the precision you are trying to gain by using uint64.
r=uint64(308436464205151562) outputs for uint64(r) 308436464205151562. However, r=308436464205151562 outputs for uint64(r) 308436464205151552. A very small loss in precision, but still a loss. The Challenge set has some numbers that use all the paint if full precision math was used. If residual paint was required as an output then full precision is needed. For solutions using p=p-2*r-1 the errors in r and p may cause issues.
Very novel input parameter adjustment to allow direct solution.
That's Muller's method which is more computationally realiable than Bhaskaracharya's.
Nice bisecting search method and anonymous function for clean appearance.
Return the largest number that is adjacent to a zero
Given an unsigned integer x, find the largest y by rearranging the bits in x
Back to basics 23 - Triangular matrix
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Cubic Integer Constrained Solution
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GJam 2013 Veterans: Baby Height Prediction
PACMAT 07 - Optimized Ghosts, PAC 2X Ghost Speed, 4 Lives; Interactive Download
Checkerz_000 Kamikazi Kings
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