Problem 2023. Is this triangle right-angled?
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among a,b,c., specify the hypotenuse.
that's the tricky part here ;) Check all combinations - too bad 'combvec' doesnt work here
Passes for True, but Failing when I get to false test?? Not sure at the moment what I could be missing.
I'd like to suggest an additional test case such as
a = sqrt(10); b = 3; c = 1;
Here the result is "true", but some of the existing solutions won't work because of rounding errors.
interesting!
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