For a given number between 1-365 (a day number in a non leap year), you should check which day of which month it is.
n=35 should give back 4 Feb.
Hi Hassan: Thanks for the problem! You might want to be clear that this is for (I assume) a non leap year.
Thanks Ned, DONE ;)
Find all elements less than 0 or greater than 10 and replace them with NaN
Distance walked 3D
Right and wrong
Bottles of beer
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