Problem 240. Project Euler: Problem 6, Natural numbers, squares and sums.
The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.
Find the difference between the sum of the squares of the first N (where N is the input) natural numbers and the square of the sum.
Thank you to Project Euler Problem 6
Solution Stats
Problem Comments

2 Comments
A problem where one must be at least a little careful about floating point arithmetic. It might have been interesting if one of the test cases were x=1e5 or larger. Even more interesting if the execution time were a factor in the "score". These factors might impact how the problem would be best solved.
@ Doug Hall, I have solved all the problems in the series. However, I have not received the badge and the associated scores on completion of the series. Can you please look into this?
Solution Comments
Show commentsProblem Recent Solvers2070
Suggested Problems

1880 Solvers

Project Euler: Problem 2, Sum of even Fibonacci
2201 Solvers

472 Solvers

Arrange vector in ascending order
765 Solvers

Create an nbyn null matrix and fill with ones certain positions
567 Solvers
More from this Author51
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!