The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.
Find the difference between the sum of the squares of the first N (where N is the input) natural numbers and the square of the sum.
Thank you to Project Euler Problem 6
A problem where one must be at least a little careful about floating point arithmetic. It might have been interesting if one of the test cases were x=1e5 or larger. Even more interesting if the execution time were a factor in the "score". These factors might impact how the problem would be best solved.
@ Doug Hall, I have solved all the problems in the series. However, I have not received the badge and the associated scores on completion of the series. Can you please look into this?
My solution is failing,please help me out
1. You used the wrong formula for the sum of the squares of the the first x natural numbers. 2. Also, your implementation of the square of the sum of the first x natural number is incorrect. 3. Finally, You are to subtract (1) from (2) not the other way round.
How can I view the solution?
can someone explain what the value and size of a correct answer means.
I think simpler is impossible. The only thing is that it needs 8 operations...
:(
For loops, not cool!
William, Why are for loops not cool?
Return the 3n+1 sequence for n
4952 Solvers
246 Solvers
Output any real number that is neither positive nor negative
239 Solvers
Area of an equilateral triangle
1549 Solvers
1097 Solvers