Problem 44309. Pi Digit Probability

Solution 2642689

Submitted on 2 Jul 2020 by Rafael S.T. Vieira

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Test	Status	Code Input and Output
1	Pass	N = 101; n = 3; y_correct = 0.1200; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match')))) % modified from the comment of Alfonso on https://www.mathworks.com/matlabcentral/cody/problems/44343
2	Pass	N = 201; n = 6; y_correct = 0.0750; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))
3	Pass	N = 202; n = 6; y_correct = 0.0796; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))
4	Pass	N = 203; n = 6; y_correct = 0.0792; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))
5	Pass	N = 1001; n = 9; y_correct = 0.1050; assert(abs(pidigit(N,n)-y_correct)<0.0001) assert(~any(cellfun(@(x)ismember(max([0,str2num(x)]),[101,201,202,203,1001]),regexp(fileread('pidigit.m'),'[\d\.\+\-\*\/]+','match'))))

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