Problem 264. Find the "ordinary" or Euclidean distance between A and Z
A, B and Z define three points in the 3D Euclidean space of the form: A = [x1;y1;0]; B = [x2;y2;0]; Z = [x2;y2;z];
Find the Euclidean distance between A and Z where
A = [1,0,0]; B = [5,3,0]; Z=[5,3,3];
>> euclidean(A,B,Z)
ans = 5.830951894845301
Your function should be able to handle 1 x 3 vectors or 3 x 1 vectors for all input parameters: A,B and Z. Z need not be 1 x 3 if A and B are. So 1x3,1x3,3x1 inputs, corresponding A, B and Z, are possible function input vectors.
HINT: use the Pythagorean formula.
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Your solution is the best and yes I did alter/correct the test suite. Thanks.
To repeat bmtran's question: Does B have anything to do with the problem?
B is a red herring. I originally conceived the problem in 2D and then extended it to 3D. So you really only need A and Z vectors. However, B can still be used but this creates a more complex solution which you don't want. Sorry if you felt misled, this was my first attempt at trying to upload an interesting problem that was hopefully not too difficult to solve. :)
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