given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Add two numbers
Reverse the vector
Project Euler: Problem 7, Nth prime
2倍してみよう - ここからスタート！
Remove the positive integers.
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