Problem 81. Mandelbrot Numbers
z(1) = c
z(n+1) = z(n)^2 + c
For any complex c, we can continue this iteration until either abs(z(n+1)) > 2 or n == lim, then return the iteration count n.
- If c = 0 and lim = 3, then z = [0 0 0] and n = 3.
- If c = 1 and lim = 5, then z = [1 2], and n = length(z) or 2.
- If c = 0.5 and lim = 5, then z = [0.5000 0.7500 1.0625 1.6289] and n = 4.
For a matrix of complex numbers C, return a corresponding matrix N such that each element of N is the iteration count n for each complex number c in the matrix C, subject to the iteration count limit of lim.
If C = [0 0.5; 1 4] and lim = 5, then N = [5 4; 2 1]
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Shlomo Geva
on 28 Nov 2020
Broken ink to Cleve Moler's PDF
goc3
on 30 Nov 2020
Thanks for noticing that, @Shlomo Geva. The link has been fixed.
Andreas
on 17 Jul 2023
Really nice problem, and great very simple solution by the community.
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